# Question: How Many Three Digit Numbers Can Be Formed Using The Digits 2 3 4 5 6 If Digits Can Be Repeated?

## How many three digits numbers can be formed using 2 3 4 and 5 with the digits being repeated?

Answer: There are 24 three digits numbers..

## What is the sum of all 4 digit numbers formed using the digits 2 3 4 and 5 without repetition?

Answer and Explanation: The sum of all the 4-digit numbers formed using the digits 2, 3, 4, and 5 (without repetition) is 93, 324.

## What are all the possible combinations of 3 numbers 0 9?

Originally Answered: How many possible combinations are there on a combination lock with three dials each having numbers 0 through 9? 000 to 999 inclusive so 10^3 or 1000 possibilities.

## How many combinations of 3 numbers can 5 numbers make?

10 possible combinationsSo 5 choose 3 = 10 possible combinations.

## How many even numbers can be formed from the digits?

The last digit is 2, 4, or 6. Since the first digit cannot be zero, you have five choices for the first digit, five choices for the second digit, and four choices for the third digit, giving 5⋅5⋅4⋅3=300 four digit even numbers that end in 2, 4, or 6.

## How many 4 digits number has sum of their digits is four?

Four digit numbers =4⋅3⋅2⋅1=24 ways we can form a four digit number. Since it’s a 4 digit number, each digit will appear 6=24/4 times in each of units, tens, hundreds, and thousands place. Therefore, the sum of digits in the units place is 6(1+2+5+6)=84.

## How many 4 digit numbers can be formed from the digits 1 2 3 4 5 6 and 7 which are divisible by 5 when none of the digits are repeated?

Answer is 840! This is a question of permutation and combination. We have to make 4 digit number without repetition using 1,2,3,4,5,6,7.

## How many combinations are there for a 3 Number Lock?

9999 possiblesA standard 3-digit lock has 999 possible combinations, which is why the 4- digit locks cost a bit of a step more money, as they have 9999 possibles.

## How many numbers not exceeding 10000 can be made using the digits 2 4 5 6 8 if repetition of digits is allowed?

Since repetition is allowed, any of the 5 digits (2,4,5,6,8) can be placed in unit place, tens place and hundreds place….Permutation and Combination #79.79. How many numbers not exceeding 10000 can be made using the digits 2,4,5,6,8 if repetition of digits is allowed?A. 740B. 9999C. 780D. 820

## How many even numbers of 5 digits can be formed with the digits 1 2 3 4 and 5?

You can make 1080 5-digit even numbers from 1,2,3,4,5,6,7 if no digit is repeated. There are total 5 places.

## How many three digit even numbers can be formed from the digits 3 2 0 and 7 if each digit can be used at most once?

12 threeEven numbers will be boxed. Therefore, 12 three-digit even numbers can be formed out of the digits 3, 2, 0 and 7 without repetition.

## How many 3 digit numbers can be formed from the digits?

So, required number of ways in which three digit numbers can be formed from the given digits is 5×4×3=60.

## How many different 3 digit sequences can be formed using the digits 0 1 9 if repetition of digits is not allowed?

If each digit must be distinct, then no repetition is allowed and the number of possibilities is: nine for the first digit [1-9], times nine (including zero) for the second digit, times eight for the third digit, for a total of 648 different 3-digit numbers.

## How many 4 digit numbers can be formed from the digits 2 3 5 6 7 and 9 which are divisible by 5 and none of the digits are repeated?

Now you have 5 digits – 2, 3, 6, 7, 9 remaining. So you can select 5 digits for tens place and as repeatation is not allowed, for hundreds place you can select remaining 4 digits. So final answer is 4 * 5 * 1 = 20 numbers can be formed. You can select 2 digits out of 5 digits given in C(5,2) = 20 ways.

## How many four digit numbers can be formed using 7 5 0 2 only once in a Number?

2) A digit can be used only once. 3) To form a n-digit number, possible numbers would be n!. 4) Hence, the answer would be 4! = 24.

## How many four digit numbers can be formed from the digits 12345 that are divisible by 4?

Without repetition there would be 24 numbers divisible by 4 using these digits. There are six combinations for each ending of 12, 24, 32 and 52 (ex. 3412, 3512, 4312, 4512, 5312, 5412) so 4 x 6 = 24 combinations. If you can repeat digits there are are many more combinations.

## How many three digit numbers can be formed using the digits 0 to 9?

There are 10 possibilities (0-9). The 3rd digit must be odd in order for the number to be odd. There are 5 possibilities (1, 3, 5, 7, 9).

## How many 3 digit even numbers can be formed from the digits 0 1 2 3 4 and 5 when none of the digits are repeated?

Therefore total three digit even numbers formed from the digits 0 ,1, 2, 3, 4, 5 and 6 such that no repetition of digit is allowed is 105.

## What is the sum of all 4 digit numbers that can be formed using the digits 1 2 3 4 where repetition of digits is allowed?

The digits are evenly dispersed, so each digit appears 120/5 = 24 times in the 1000’s place. Summing the 1000’s place numbers, we get 24 * (0+1+2+3+4) * 1000 = 240000.

## How many 2 digit numbers are there?

90 twoHow many two-digit numbers are there? There are 90 two-digit numbers in all.

## How many 3 digits numbers are there with no digit repeated?

648 numbersAnswer: There are 648 numbers that are 3 digits numbers such that none of the digits are repeated.